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1.
全国各级成人学校基本情况BasicStatisticsofAdultSchoolsinChinabyLevel&Type单位:万人in10thousand学校数(所)No.ofSchools毕业生数Graduates招生数Entrants在校学生数E...  相似文献   

2.
1997年全国各级学校基本情况BasicStatisticsofRegularSchoolsinChinabyLevel&Type单位:万人Unit:in10Thousand学校数No.ofSchools合计Total教职工数Teachers,Sta...  相似文献   

3.
全国各级普通学校基本情况BasicStatisticsofRegularSchoolsinChinabyLevel&Type单位:万人in10thousand学校数(所)No.ofSchools毕业生数Graduates招生数Entrants在校学生...  相似文献   

4.
试论唐人写经题记的原始著作权意义陈泽奎OnConsciousnessofOriginalCopyrightSeeninInscriptionsofBuddhistScripturesinDunhuangMss.oftheTangDynasty¥Che...  相似文献   

5.
on and Homogenization of Diamond Film in the Multifilament CVD SystemTX1IntroductionThehot-filamentchemicalvapordeposition(HFC...  相似文献   

6.
Peroxides Based on Immobilization of Redox Organic Dyes and Horseradish Peroxidase in Polyester Ionomer FilmTX1IntroductionOrg...  相似文献   

7.
这一模式运用于阅读课文教学中行之有效。下面以 SEFC Book IBL62为例,简述该模式诸环节。 导。导入是学生阅读课文之前在教师指导下进行的。这一环节的目的在于集中学生的注意力,有效地激发学生的学习兴趣和求知欲望,从而自然地过渡到新内容的教学。 如 Sac Paulo Fire,可采用直观教具导人法: T:What’s this in my hand? S:It’s a lighter. T:What does a lighter produce? S:Fire. T:What’s the use of the …  相似文献   

8.
1995年全国各级成人学校基本情况BasicStatisticsofAdultSchoolsinChinabyLevel&Typein10thousand(A):ofthetotal:TheRegularShort-CycleCoursesinRad...  相似文献   

9.
全国各级成人学校基本情况BasicStatisticsofAdultSchoolsinChinabyLevel&Type¥//(A):Ofthetotal:TheRegularShort-CycleCoursesinRadio/TVUniversit...  相似文献   

10.
中国新样文殊与日本文殊三尊五尊像之比较研究   总被引:1,自引:1,他引:1  
中国新样文殊与日本文殊三尊五尊像之比较研究孙修身AComparisionbetweentheFiguresofManjusriandAttendantsinChinaandinJapanSunXiushenThepresentpapercitesfi...  相似文献   

11.
1 Introduction DavidHilbertposedtwentythreeproblemsinhisspeechattheInternationalCongressofMathemati ciansinParisin 190 0 .AtranslationofthetextofHilbertproblemsaspublishedintheBulletinoftheAmericanMathematicalSocietyof 190 3wasrestatedinProceedingoftheSympos…  相似文献   

12.
London(1)     
William BlakeI wander thro(2)each charter’d(3)street,Near where the charter’d Thames(4) does flow,And mark(5)in every faceI meetMarks of weakness, marks of woe.In every (6) cry of every Man,In every Infant’s cry offear,in every voice, in every ban(7),The mind-forg’…  相似文献   

13.
定理 如果△ABC的面积为S ,点D、E、F依次分△ABC三边所成的比分别为λ1、λ2 、λ3 ,那么S△DEF =1 λ1λ2 λ3 (1 λ1) (1 λ2 ) (1 λ3 ) S .  证明 先看点D、E、F均在三边上 ,由已知得  AD∶DB =λ1,BE∶EC =λ2 ,CF∶FA =λ3 ,于是有AD =λ11 λ1AB ,BD =11 λ1AB ,BE =λ21 λ2BC , EC =11 λ2BC ,CF =λ3 1 λ3 CA , FA =11 λ3 CA .∴S△ADF =12 AD·AFsinA=12 · λ11 λ1AB· 11 λ3CA·sinA= λ1(1 λ1) (1 λ3 ) · 12 AB·AC·sin…  相似文献   

14.
INTRODUCTIONThemagneticandtransportpropertiesofthinmagneticmultilayershaveattractedconsiderableattentionduringthepastyears.Sincediscoveryofnegativegiantmagnetoresistance (GMR)byBaibichetal.inFe/Crmultilayers (Baibich ,1 998) ,extensiveresearchhasbeendonecon c…  相似文献   

15.
Section1 :BreakdownofForcesYoucanbreakdownforcesintoseveralcomponentseaslily.Forexample,theforceF1 at30degreecanbebro kenintotwoforces:FxandFy,andFx=cos30°×F1 ,Fy=sin30°×F1 .Section2 .TwoDimensionalForcesintoOneYoucancombinetwoforcesintoone.SupposeTompushedaboxwit…  相似文献   

16.
OrdersofMagnitudeReasoningAppliedinSelectingShieldYuZhongyuanHuMin*LiuZhenyu**(ShanghaiTiedaoUniversity,*ShanghaiUniversity,*...  相似文献   

17.
本文先给出三角形的外接圆半径、内切圆半径与面积之间的一个不等式 .定理 1 若三角形的外接圆半径为R ,内切圆半径为r,面积为S ,则Rr≥2 39S .证 设△ABC的三边长为a、b、c,由S =abc4R ,得  1ab 1bc 1ca=c4RS a4RS b4RS=a b c4RS =a b c4R·12 (a b c)r=12Rr,即  1ab 1bc 1ca=12Rr. ( 1)∵ S =12 absinC =12 bcsinA =12 casinB ,∴  1ab 1bc 1ca=sinC2S sinA2S sinB2S   =sinA sinB sinC2S .又易证 si…  相似文献   

18.
1 Introduction In 1988,Yoshizawaandco workers[1] reportedforthefirsttimeonanewgoodsoftmagneticalloycalledFinemet.Itconsistedofultrafinegrainstructurepre paredbythecrystallizationofFe Si BamorphousalloywithadditionsofCuandNb[1~ 3] .Theformationofthisparticularst…  相似文献   

19.
INTRODUCTIONFormostofthepast WorldWarⅡera,bankingregulationproceededsmoothly .Sincefewbankfailuresoccurred ,academicsandthepublicpaidlittleattentiontothetopic.Becauseofvariousfactors,bankfailureshavebecomecommonsincethe 1 980sandtheinternationalcommunityhas…  相似文献   

20.
若三角形的外接圆半径为R ,内切圆半径为r ,面积为S△ ,则S△ ≤ 332 Rr .1 S△ ≤ 332 Rr的证明方法证法 1 易证S△ =4Rrcos A2 cos B2 cos C2 ,及cos A2 cos B2 cos C2 ≤ 338,于是S△ ≤ 332 Rr .证法 2 ∵S△ =rs ,又易证s≤ 332 R ,故S△ ≤ 332 Rr .  证法 3 ∵S△ =Rr(sinA sinB sinC) ,又sinA sinB sinC≤ 332 ,于是S△ ≤ 332 Rr .证法 4 ∵S△ =12 (a b c)r ,又易证a b c≤ 33R ,故S△ ≤ 332 Rr .综上可知 ,如能巧用形式各…  相似文献   

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