摘 要: | 计算 :(2 0 0 0 2 - 2 0 0 6 ) (2 0 0 0 2 +3997)× 2 0 0 11997× 1999× 2 0 0 2× 2 0 0 3.解 先用字母表示数 ,然后通过适当的恒等变形 ,即可求得原式的值 .设 2 0 0 0 =a ,则原式 =[a2 - (a +6 ) ](a2 +2a - 3) (a +1)(a - 3) (a - 1) (a +2 ) (a +3)=(a +2 ) (a - 3) (a +3) (a - 1) (a +1)(a - 3) (a - 1) (a +2 ) (a +3)=a +1.∴ 原式 =2 0 0 1.一道数学计算题的巧解@柯小舟!广西…
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