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关于同余式2n≡7(modn)的解
引用本文:黄忠铣. 关于同余式2n≡7(modn)的解[J]. 南平师专学报, 2010, 29(5): 12-13
作者姓名:黄忠铣
作者单位:武夷学院数学与计算机系,福建武夷山354300
摘    要:证明了2n≡7(modn)(n〉1)在[2,105]中仅有解n=25=5·5.及当整数m〉1满足2m≡7(modm)时,有n=2m-1是2n-6≡1(modn)的解.更进一步地,若整数m〉1满足2m≡2k+1(modm),则n=2m-1是2n-2k≡1(modn)的解.

关 键 词:同余式  素数  因子

Solution on the Congruence
HUANG Zhongxian. Solution on the Congruence[J]. Journal of Nanping Teachers College, 2010, 29(5): 12-13
Authors:HUANG Zhongxian
Affiliation:HUANG Zhongxian(Department of Mathematics and Computer,Wuyi University, Wuyishan,Fujian 354300)
Abstract:The author proves the congruence2n≡7(modn)only one solution n=25=5·5 in the interval [2,105]. And when m1 satisfy the congruence 2m≡7(modm) then n=2m-1is a solution of the congruence 2n-6≡1(modn) . Further more, when m1 satisfy the congruence 2m≡2k+1(modm) then n=2m-1 is a solution of the congruence 2n-2k≡1(modn).
Keywords:congruence  prime  factor
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